Namespace iteration

Question

I have a namespace similar to this:

Namespace (aTQ = No, bE = No, bEQ = No, b = No, bQ = No, c = No, c = None, cJ = None, d = None, g = None, jR = ['xx', '015'], lC = None, l = None)

How can I iterate over it so that I can find and replace the value “xx” for the key “jR”?

Answer 1

I'm not sure what you know in advance (the name jR or only one name has the value not None ), but you can try using vars (), which, like __dict__ , should be a dict that has names in your namespace as its keys . So, if you have the string 'jR' somewhere,

 vars()['jR'] = vars()['jR'][0] 

Similarly, you can get the same dict using namespace.__dict__ instead of vars()

will leave you the first value in ['xx','015'] as the only value for jR .

EDIT: To be clear, since vars() and __dict__ both return dicts, you can iterate through them:

 for k in namespace.__dict__: if namespace.__dict__[k] is not None: <<do something>>