How to check all elements in a <ul> list using Selenium WebDriver?

Question

Is it possible to skip all li elements of the <ul> </ul> element. Let's say I have an unknown number of li elements, so one way to scroll through them would be to impose a for loop with the maximum number of li s, say 100, and impose try and catch .

 try{ for (int i=0; i<100; i++) { driver.findElement(By.xpath("//div[@id='...']/ul/li[i]")); } } catch {...} 

However, it does not recognize index i ? How can I recognize him?

Is there a better way?

Answer 1

Webdriver has a findElements API that can be used for this purpose.

 List<WebElement> allElements = driver.findElements(By.xpath("//div[@id='...']/ul/li")); for (WebElement element: allElements) { System.out.println(element.getText()); } 

Answer 2

Your source code may work if you infer index i from a string as follows:

 try { for (int i=0; i<100; i++) { driver.findElement(By.xpath("//div[@id='...']/ul/li["+i+"]")); } } catch {...} 

Answer 3

 List<WebElement> allElements = driver.findElements(By.xpath("//div[@id='...']/ul/li")); int s=allElements.size(); for(int i=1;i<=s;i++){ allElements = driver.findElements(By.xpath("//div[@id='...']/ul/li")); allElements.get(i).click(); } 

Use this

Answer 4

Your goal is to get all li within ul. So he must find ul first, and then all li in that ul. You can use the following Selenium Java code:

 WebElement ul_element = driver.findElement(By.xpath("//ul[@class='list-unstyled']")); List<WebElement> li_All = ul_element.findElements(By.tagName("li")); System.out.println(li_All.size()); for(int i = 0; i < li_All.size(); i++){ System.out.println(li_All.get(i).getText()); } //OR for(WebElement element : li_All){ System.out.println(element.getText()); }