Php imagecopyresampled adds black background

Question

I have a script-sized image that takes a 130x81 image and adds it to a 130x130 image, when the imagecopyresampled function runs it, it adds a black background to the remaining space, although the base image is white. Code below, I could really appreciate some help.

The image that I am trying to combine into the created php 130x130 is:

$width = 130; $height = 130; $filename = 'process-add.jpg'; //130x81px jpg $this->_image = imagecreatefromjpeg($filename); $background = imagecreatetruecolor(130,130);//create the background 130x130 $whiteBackground = imagecolorallocate($background, 255, 255, 255); imagefill($background,0,0,$whiteBackground); // fill the background with white imagecopyresampled($background, $this->_image,(130-$width)/2,(130-$height)/2, 0, 0, $width, $height, $width, $height); // copy the image to the background ImageJpeg ($background,null,100); //display 

I read a few posts to add:

 imagealphablending($background, false); 

into code that should fix it, but that doesn't make any difference.

Thanks in advance!

Answer 1

It was agreed. The problem was the width and height when calling imagecopyresampled. See the code block below:

 <? ini_set('allow_url_fopen', true); $filename = 'http://img.yessy.com/1402152287-17201a.jpg'; // 130x81 $image = imagecreatefromjpeg($filename); list($originalWidth, $originalHeight) = getimagesize($filename); // Size of image to create $width = 130; $height = 130; $background = imagecreatetruecolor($width, $height);//create the background 130x130 $whiteBackground = imagecolorallocate($background, 255, 255, 255); imagefill($background,0,0,$whiteBackground); // fill the background with white imagecopyresampled($background, $image, 0, ($height - $originalHeight) / 2, 0, 0, $originalWidth, $originalHeight, $originalWidth, $originalHeight); // copy the image to the background header("Content-type: image/jpeg"); ImageJpeg ($background,null,100); //display ?>