Java: Python range equivalent (int, int)?

Question

Does Java have an equivalent Python method range(int, int) ?

Answer 1

Guava also provides something similar to the Python range :

 Range.closed(1, 5).asSet(DiscreteDomains.integers()); 

You can also implement a fairly simple iterator to do the same using the Guava AbstractIterator:

 return new AbstractIterator<Integer>() { int next = getStart(); @Override protected Integer computeNext() { if (isBeyondEnd(next)) { return endOfData(); } Integer result = next; next = next + getStep(); return result; } }; 

Answer 2

Old question, new answer (for Java 8)

  IntStream.range(0, 10).forEach( n -> { System.out.println(n); } ); 

or using method references:

 IntStream.range(0, 10).forEach(System.out::println); 

Answer 3

I am working on a small Java utils library called Jools and contains a Range class that provides the functions you need (there is a loadable JAR).
The constructors are either Range(int stop) , Range(int start, int stop) , or Range(int start, int stop, int step) (similar to a for loop), and you can either iterate over it using a lazy evaluation, or use the method toList() to explicitly get a list of ranges.

 for (int i : new Range(10)) {...} // i = 0,1,2,3,4,5,6,7,8,9 for (int i : new Range(4,10)) {...} // i = 4,5,6,7,8,9 for (int i : new Range(0,10,2)) {...} // i = 0,2,4,6,8 Range range = new Range(0,10,2); range.toList(); // [0,2,4,6,8] 

Answer 4

Since Guava 15.0, Range.asSet () is deprecated and should be removed in version 16. Instead, use the following:

 ContiguousSet.create(Range.closed(1, 5), DiscreteDomain.integers()); 

Answer 5

 public int[] range(int start, int stop) { int[] result = new int[stop-start]; for(int i=0;i<stop-start;i++) result[i] = start+i; return result; } 

Forgive any syntax or style errors; I usually program in C #.

Answer 6

You can use the following code snippet to get a set of integers:

  Set<Integer> iset = IntStream.rangeClosed(1, 5).boxed().collect (Collectors.toSet()); 

Answer 7

 public int[] range(int start, int length) { int[] range = new int[length - start + 1]; for (int i = start; i <= length; i++) { range[i - start] = i; } return range; } 

(Long answer, just to say no)

Answer 8

Groovy nifty The range class can be used with Java, although this, of course, is not like groovy.

Answer 9

The "Functional Java" library allows you to program this way to a limited extent, it has a range () method that creates an instance of fj.data.Array.

Cm:

• http://functionaljava.googlecode.com/svn/artifacts/3.0/javadoc/fj/data/Array.html#range%28int,%20int%29

Similarly, the Totally Lazy library offers a lazy range method: http://code.google.com/p/totallylazy/

Answer 10

If you want to use it in the same way as in the Python loop, Java goes well with the for statement, which makes this structure unnecessary for this purpose.