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Can "use" completely replace "typedef" in all cases?

I know that using can do something typedef cannot.

I'm just wondering if using completely replace typedef in all cases?

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c ++ types c ++ 11 typedef using
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Yes, he can, a quote from the draft standard (my bold accent)

7.1.3 typedef specification [dcl.typedef]

2 The typedef name can also be entered using the alias declaration. the identifier after the using keyword becomes typedef-name and the optional spec-fi-seq attribute following the identifier refers to this typedef-name. It has the same semantics as if it were introduced by the typedef specification.

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