String.Indexof() with several overloads:
Dim jstr = "How much wood could a woodchuck chuck if a woodchuck..." ' Find a character from a starting point ndx = jstr.IndexOf("w"c) ' == 2 (first w) ' or within a range: ndx = jstr.IndexOf("o"c, 12) ' == 15 first o past 12 (cOuld) 'Find a string ndx = jstr.IndexOf("wood") ' == 9 ' ...from a starting point ndx = jstr.IndexOf("wood", 10) ' == 22 (WOODchuck) ' ...or in part of the string ndx = jstr.IndexOf("chuck", 9, 15) ' -1 (none in that range) ' using a specified comparison method: ndx = jstr.IndexOf("WOOD", StringComparison.InvariantCultureIgnoreCase) ' 9 ndx = jstr.IndexOf("WOOD", nFirst, StringComparison) ndx = jstr.IndexOf("WOOD", nFirst, nLast, StringComparison)
There is also a String,LastIndexOf() method String,LastIndexOf() to get the last occurrence of something on a string and with a lot of overloads.
Available on MSDN or in the object browser (VIEW menu | Object Browser) in VS near you.
i = Hostname.Indexof(Environment.Newline, 1)
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