Matching node based on brother value with XPath

Question

Having an XML document as follows:

<?xml version="1.0" encoding="UTF-8"?> <records type="array"> <record> <name>svn</name> <record-type>A</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">69075</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>xxx.xxx.xxx.xxx</data> </record> <record> <name>domain.tld.</name> <record-type>NS</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">xxx</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>domain.tld.</data> </record> <record> <name>blog</name> <record-type>A</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">xxx</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>xxx.xxx.xxx.xxx</data> </record> </records> 

How to match all the names / records / record / having a type with a value of "A" as a kinship / record / record / record?

Answer 1

Found:

 /records/record/name[../record-type/text() = "A"] 

Answer 2

You can also filter the parent element with your child elements:

/records/record[record-type[text()='A']]/name

Answer 3

Surprisingly, none of the answers to this old question provide the simplest XPath solution.

This simple XPath

 /records/record[record-type = "A"]/name 

The choice

 <name>svn</name> <name>blog</name> 

upon request.

Answer 4

 /records/record[record-type='A']