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Java regex metal throw exception not found for match if pattern found in string

I'm dying trying to figure out why the regex won't match. Any help is much appreciated. I go along the line of the web page (this works great), but I need to pull out the links for each line. The application will check if there is a link in the line, but I need to actually pull out the url. to help?

Pattern p = Pattern.compile("^.*href=\"([^\"]*)"); Matcher m = p.matcher(result); String urlStr = m.group(); links.add(urlStr);

The error message I get is the following:

 Exception in thread "main" java.lang.IllegalStateException: No match found at java.util.regex.Matcher.group(Matcher.java:485)

Despite the fact that in the "result" there is a link to the link (hxxp: //www.yahoo.com).

References

is an ArrayList fyi. Thanks in advance!

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2 answers

Ok, so I figured it out. The only problem: my regex should have been

 ".*href=\"([^\"]*?)\".*"

Who made the code

 private String regex = ".*href=\"([^\"]*?)\".*"; private Pattern p = Pattern.compile(regex); Matcher m = p.matcher(result); if (m.matches()) { String urlStr = m.group(1); links.add(urlStr); }

So that was my regex problem, I had to use '?' so as not to be greedy, I think!

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first call

 m.find();

or

 m.matches();

and then you can use m.group() if the match is successful.

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