QtQuick, how do I know if the application was compiled in debug or release mode?

Question

In Qt / C ++, there is a QT_DEBUG macro to know when it compiles during debugging or release.

Is there a way to find out if an application running in debug mode o works in a QML file?

Answer 1

You can use context properties to open C ++ objects for QML:

#include <QtGui/QGuiApplication> #include <QQmlContext> #include <QQuickView> #include "qtquick2applicationviewer.h" int main(int argc, char *argv[]) { QGuiApplication app(argc, argv); QtQuick2ApplicationViewer viewer; #ifdef QT_DEBUG viewer.rootContext()->setContextProperty("debug", true); #else viewer.rootContext()->setContextProperty("debug", false); #endif viewer.setMainQmlFile(QStringLiteral("qml/quick/main.qml")); viewer.showExpanded(); return app.exec(); } 

main.qml:

 import QtQuick 2.2 Item { id: scene width: 360 height: 360 Text { anchors.centerIn: parent text: debug } } 

It is not possible to define this purely from within QML.

Answer 2

Do you need to know this at runtime or at compile time? Macros are used at compile time, QML is executed at runtime, so there is no difference for a compiled application between "debug" and "release".

Decision:

 Create a class with const property declared in next way: class IsDebug : public QObject { QOBJECT Q_PROPERTY( IsDebug READ IsCompiledInDebug ) // Mb some extra arguments for QML access public: bool IsCompiledInDebug() const { return m_isDebugBuild; } IsDebug() #ifdef QT_DEBUG : m_isDebugBuild( true ) #else : m_isDebugBuild( false ) #endif {} private: const bool m_isDebugBuild; }