select partition_name,column_name,high_value,partition_position from ALL_TAB_PARTITIONS a , ALL_PART_KEY_COLUMNS b where table_name='YOUR_TABLE' and a.table_name = b.name;
This query specifies the column name, which is used as a key and valid values. make sure you enter valid values ( high_value ). Otherwise, if the default partition is specified, it will be there.
EDIT:
I suppose your TABLE DDL will be like that.
CREATE TABLE HE0_DT_INF_INTERFAZ_MES ( COD_PAIS NUMBER, FEC_DATA NUMBER, INTERFAZ VARCHAR2(100) ) partition BY RANGE(COD_PAIS, FEC_DATA) ( PARTITION PDIA_98_20091023 VALUES LESS THAN (98,20091024) );
This means that I created a section with several columns that contains a value less than the compound range (98,20091024);
This is the first COD_PAIS <= 98 and also FEC_DATA < 20091024
Combinations and result:
98, 20091024 FAIL 98, 20091023 PASS 99, ******** FAIL 97, ******** PASS < 98, ******** PASS
So, below the INSERT ORA-14400 does not work; because (98,20091024) in INSERT is equal to EQUAL for a unit in DDL , but no less.
SQL> INSERT INTO HE0_DT_INF_INTERFAZ_MES(COD_PAIS, FEC_DATA, INTERFAZ) VALUES(98, 20091024, 'CTA'); 2 INSERT INTO HE0_DT_INF_INTERFAZ_MES(COD_PAIS, FEC_DATA, INTERFAZ) * ERROR at line 1: ORA-14400: inserted partition key does not map to any partition
But we try ( 97 , 20091024), it goes through
SQL> INSERT INTO HE0_DT_INF_INTERFAZ_MES(COD_PAIS, FEC_DATA, INTERFAZ) 2 VALUES(97, 20091024, 'CTA'); 1 row created.