Close: First you call ExcelFile , but then you call the .parse method and pass it the sheet name.
>>> xl = pd.ExcelFile("dummydata.xlsx") >>> xl.sheet_names [u'Sheet1', u'Sheet2', u'Sheet3'] >>> df = xl.parse("Sheet1") >>> df.head() Tid dummy1 dummy2 dummy3 dummy4 dummy5 \ 0 2006-09-01 00:00:00 0 5.894611 0.605211 3.842871 8.265307 1 2006-09-01 01:00:00 0 5.712107 0.605211 3.416617 8.301360 2 2006-09-01 02:00:00 0 5.105300 0.605211 3.090865 8.335395 3 2006-09-01 03:00:00 0 4.098209 0.605211 3.198452 8.170187 4 2006-09-01 04:00:00 0 3.338196 0.605211 2.970015 7.765058 dummy6 dummy7 dummy8 dummy9 0 0.623354 0 2.579108 2.681728 1 0.554211 0 7.210000 3.028614 2 0.567841 0 6.940000 3.644147 3 0.581470 0 6.630000 4.016155 4 0.595100 0 6.350000 3.974442
What you are doing is calling a method that lives in the class itself, and not in an instance that is in order (although not very idiomatic), but if you do, you will also need to pass the sheet name
>>> parsed = pd.io.parsers.ExcelFile.parse(xl, "Sheet1") >>> parsed.columns Index([u'Tid', u'dummy1', u'dummy2', u'dummy3', u'dummy4', u'dummy5', u'dummy6', u'dummy7', u'dummy8', u'dummy9'], dtype=object)
DSM Jun 12 '13 at 10:52 2013-06-12 10:52
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