Types when destroying arrays

Question

function f([a,b,c]) { // this works but a,b and c are any } 

is it possible to write something like that?

 function f([a: number,b: number,c: number]) { // being a, b and c typed as number } 

Answer 1

 function f([a,b,c]: [number, number, number]) { } 

I have added text to this answer so that it does not appear in the VLQ code-only queue. As you can see, the question is basically “What is the syntax for this task?”, And the sample code above shows what the syntax looks like. Nothing to explain.

Answer 2

Yes it is. In TypeScript, you do this using array types in a simple way by creating tuples.

 type StringKeyValuePair = [string, string]; 

You can do what you want by naming the array:

 function f(xs: [number, number, number]) {} 

But you would not specify an intermediate parameter. Another possibility is to use pair destructuring:

 function f([a,b,c]: [number, number, number]) {}