PHP 7 return type declarations - fatal error

Question

I wanted to try out PHP 7 return type declarations (for this I use PHP 7RC3 for windows).

wanted to start with something very simple:

function getme() : integer { return 434; } echo getme(); 

but this gives me a fatal error:

Fatal error: Uncaught TypeError: getme () return value must be an integer instance, integer return

then I also tried to display the return value, but return (integer) 434; or return (int) 434; gives me the same error;

Finally, I also tried:

 function getme() : integer { $i = 434; return (integer) $i; } echo getme(); 

with the same result.

what am I doing wrong?
or what did I misunderstand here?

Thanks for any explanation and help!

UPDATE
this is why I thought I needed to use integer instead of int (special attention to Toby Allen):

from https://wiki.php.net/rfc/return_types :

Examples of misuse (...)

 // Int is not a valid type declaration function answer(): int { return 42; } answer(); 

Answer 1

No new reserved words have been added. The names int, float, string and bool are recognized and allowed as type declarations, and are prohibited from being used as class / interface / attribute names (including using class_alias).

From: https://wiki.php.net/rfc/scalar_type_hints_v5

TL / DR:

 function getme() : int { return 434; } echo getme();