You can simply use img.At(x, y).RGBA() to get the RBGA values ββfor the pixel, you just need to divide them by 257 to get an 8-bit representation. I would recommend creating your own two-dimensional array of pixels. Here's a possible implementation, change it as needed:
package main import ( "fmt" "image" "image/png" "os" "io" "net/http" ) func main() { // You can register another format here image.RegisterFormat("png", "png", png.Decode, png.DecodeConfig) file, err := os.Open("./image.png") if err != nil { fmt.Println("Error: File could not be opened") os.Exit(1) } defer file.Close() pixels, err := getPixels(file) if err != nil { fmt.Println("Error: Image could not be decoded") os.Exit(1) } fmt.Println(pixels) } // Get the bi-dimensional pixel array func getPixels(file io.Reader) ([][]Pixel, error) { img, _, err := image.Decode(file) if err != nil { return nil, err } bounds := img.Bounds() width, height := bounds.Max.X, bounds.Max.Y var pixels [][]Pixel for y := 0; y < height; y++ { var row []Pixel for x := 0; x < width; x++ { row = append(row, rgbaToPixel(img.At(x, y).RGBA())) } pixels = append(pixels, row) } return pixels, nil } // img.At(x, y).RGBA() returns four uint32 values; we want a Pixel func rgbaToPixel(r uint32, g uint32, b uint32, a uint32) Pixel { return Pixel{int(r / 257), int(g / 257), int(b / 257), int(a / 257)} } // Pixel struct example type Pixel struct { R int G int B int A int }
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