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C # using instructions inside #if DEBUG but not ship assembly

I have a function that I want to do only in Debug, but I do not want to send the DLL that this function requires. Can this be done?

I have:

#if DEBUG using MyAssembly; #endif

Of course, MyAssembly refers to the project. I would like MyAssembly.dll not to go in release mode. Could this be achieved? Will conditional ("DEBUG") help be used in this regard?

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Links that are not required are usually deleted automatically by the compiler: you can be more explicit by modifying csproj by including Condition in the PropertyGroup . Something like:

 <PropertyGroup Condition="'$(Configuration)' == 'Debug'"> <Reference Include="YourReference" /> </PropertyGroup>

(may also be <PackageReference> , etc.)

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It's perfectly fine to put the using directive in the #if DEBUG section, and it will remove that directive when compiling for debugging.

However, this is only part of the story; he will not complete your task on his own. Visual Studio also has a Links section in Solution Explorer. You will also need to remove the link for the assembly, or it will be included at creation.

I don’t remember anything in the Visual Studio user interface that will allow you to do this, but I expect it to be possible if you manually edit the Project file (it’s just an MSBuild file). Personally, I try very hard to avoid actions that require manual editing of project files. Visual Studio wants to own these files, and you can create conflicts in which you and Visual Studio overwrite each other.

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