Consider the following Python exception:
[...] f.extractall() File "C:\Python26\lib\zipfile.py", line 935, in extractall self.extract(zipinfo, path, pwd) File "C:\Python26\lib\zipfile.py", line 923, in extract return self._extract_member(member, path, pwd) File "C:\Python26\lib\zipfile.py", line 957, in _extract_member os.makedirs(upperdirs) File "C:\Python26\lib\os.py", line 157, in makedirs mkdir(name, mode) WindowsError: [Error 267] The directory name is invalid: 'C:\\HOME\\as\ \pypm-infinitude\\scratch\\b\\slut-0.9.0.zip.work\\slut-0.9\\aux'
I want to handle this specific exception - that is, a WindowsError with error number 267. However, I cannot just do the following:
try: do() except WindowsError, e: ...
Because this will not work on Unix systems where WindowsError is not even defined in the exception module.
Is there an elegant way to handle this error?
python windows exception exception-handling
Sridhar ratnakumar
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