PHP: How to get Sunday and Saturday based on date input?

Question

How can I get Sunday and Saturday of the week with a specific date?

For example:

Admission: Monday, September 28, 2009

the conclusion should be:

Sunday, September 27, 2009 12:00 - Saturday, October 3, 2009 23:59

I am thinking of using date , strtotime , mktime and time php functions.

If you have a useful feature, then this is also good.

Thanks in advance:)

Cheers, Mark

Answer 1

You use strtotime() and date()

 <?php $s = 'Monday, September 28, 2009'; $time = strtotime($s); $start = strtotime('last sunday, 12pm', $time); $end = strtotime('next saturday, 11:59am', $time); $format = 'l, F j, Y g:i A'; $start_day = date($format, $start); $end_day = date($format, $end); header('Content-Type: text/plain'); echo "Input: $s\nOutput: $start_day - $end_day"; ?> 

outputs:

 Input: Monday, September 28, 2009 Output: Sunday, September 27, 2009 12:00 PM - Saturday, October 3, 2009 11:59 AM 

Answer 2

 <?php date_default_timezone_set('Europe/London'); $datetime = new DateTime("2009-09-23 12:00:00"); // Saturday $datetime->setISODate(2009, $datetime->format("W"), 6); print "Saturday:" . $datetime->format(DATE_ATOM) . "\n"; // Sunday $datetime->setISODate(2009, $datetime->format("W"), 0); print "Sunday: " . $datetime->format(DATE_ATOM) . "\n"; ?> 

Answer 3

take a look at strtotime

i.e.

 strtotime('next sunday', strtotime($your_date_string)); 

Answer 4

echo date ("Ymd H: i: s", strtotime ("last Sunday", time ()));

echo date ("Ymd H: i: s", strtotime ("next Saturday", time ()));

Answer 5

The question with the “correct” answer is, what if the delivered date is Sunday? Then it will give you the previous Sunday instead of the current Sunday. The same question is with Saturday.

 $s = 'Monday, September 28, 2009'; $time = strtotime($s); if(date('D', $time) == "Sun"){ $start = strtotime(' 12pm', $time); } else { $start = strtotime('last sunday, 12pm', $time); } if(date('D', $time) == "Sat"){ $start = strtotime(' 12pm', $time); } else { $start = strtotime('next saturday, 12pm', $time); } $format = 'l, F j, Y g:i A'; $start_day = date($format, $start); $end_day = date($format, $end); header('Content-Type: text/plain'); echo "Input: $s\nOutput: $start_day - $end_day"; 

Answer 6

Strtotime

 $input = strtotime("Monday, September 28, 2009"); $nextSunday = strtotime("next Sunday",$input); 

Answer 7

 <?php $date = strtotime('Monday, September 28, 2009 - 1 day'); $initialString = date('l, F d, Y g:i A', $date); $end = date('l, F d, Y g:i A', strtotime( 'next saturday 11:59 pm', $date)); echo $initialString . ' - ' . $end; 

Exit: Sunday, September 27, 2009 12:00 - Saturday, October 03, 2009 23:59

Answer 8

This is what you are looking for. This is what I use.

 $beginningOfWeek = date('Ymd H:i:s', strtotime('last Sunday')); $endOfWeek = date('Ymd H:i:s', strtotime('+6 day', strtotime('last Sunday')) ); 

Answer 9

In this case, you can find my assistant Time Time Helper, it can end in 3 lines

http://normandqq.imtqy.com/Date-Time-Helper/

  $date = '2013-08-11'; $monday = Model_DTHpr::getMondayByDate($date); $sunday = Model_DTHpr::adjustDays("add",$monday,6); 

Out put:

  2013-08-05 //Monday 2013-08-11 //Sunday 

Answer 10

Get Sunday Php Code:

 echo "Today Is : " . date("dmY"); $dw = date( "w"); $dw = 7-$dw; echo "\nNext Sunday Is" .date('dm-Y', strtotime("+$dw days"));