How to enable drag and drop of a file in * .exe and get it as a parameter?

Question

What do I need to do so that my program uses a file that was dragged and dropped to its icon as a parameter?

My current main method is as follows:

 int main(int argc, char* argv[]) { if (argc != 2) { cout << "ERROR: Wrong amount of arguments!" << endl; cout << "\n" << "Programm closed...\n\n" << endl; exit(1); return 0; } Converter a(argv[1]); // ... cout << "\n" << "Programm finished...\n\n" << endl; // cin.ignore(); return 0; } 

What I really would like to do is select 10 (or so) files, drop them onto an EXE, and process them from my application.

---

EDIT:

The incomming parameter is used as the file name created in the cunstructor.

 Converter::Converter(char* file) { // string filename is a global variable filename = file; myfile.open(filename.c_str(), ios_base::in); } 

Text File Reading Method:

 string Converter::readTextFile() { char c; string txt = ""; if (myfile.is_open()) { while (!myfile.eof()) { myfile.get(c); txt += c; } } else { error("ERROR: can't open file:", filename.c_str()); } return txt; } 

---

EDIT2: Cross Out

Update:
I got to this point.

Actual main method:

 // File path as argument 

int main (int argc, char * argv []) {if (argc <2) {sob & A; <"ERROR: wrong number of arguments! Give at least one argument ... \ n" & L; <cps; cout <"\ n" <"The program is closed ... \ n \ n" <<nbsp; cin.ignore (); output (1); return 0; }

 vector<string> files; for (int g = 1; g < argc; g++) { string s = argv[g]; string filename = ""; int pos = s.find_last_of("\\", s.size()); if (pos != -1) { filename = s.substr(pos + 1); cout << "argv[1] " << argv[1] << endl; cout << "\n filename: " << filename << "\n pos: " << pos << endl; files.push_back(filename); } files.push_back(s); } for (unsigned int k = 0; k < files.size(); k++) { cout << "files.at( " << k << " ): " << files.at(k).c_str() << endl; Converter a(files.at(k).c_str()); a.getATCommandsFromCSV(); } cout << "\n" << "Programm finished...\n\n" << endl; cin.ignore(); return 0; } 

In fact, the console window appears, perhaps for 0.5 seconds, and closes again.
It does not stop at any of my cin.ignore(); Maybe he didn’t get there?

Can anyone help?

Answer 1

Your program should not do anything special other than handling command line arguments. When you drag a file into the application in Explorer, it no more than passes the file name as an argument to the program. Similarly for multiple files.

If all you expect is a list of file names, then just iterate over all the arguments, do whatever you want with them, and do it. This will work from zero to almost arbitrarily many arguments.

Answer 2

Perhaps you could write a test program as follows:

 int main(int argc, char* argv[]) { // argv[0] is not interesting, since it just your program path. for (int i = 1; i < argc, ++i) cout << "argv[" << i << "] is " << argv[i] << endl; return 0; } 

And let's see what happens after you throw different files on it.

---

EDIT: Just look at Joy's answer.

Answer 3

The answer to the main question

SEE ANSWER TO YOUR FOLLOWING PROBLEM TO SEE LOWER ANSWER

All files with drag and drop become available as argv[orderOfTheFile] ( orderOfTheFile - from 1-n) Once the windows create this order, now that is a real secret ...

In any case, let me say that I would create 26 simple text files (* .txt), from a.txt to z.txt on my desktop,
Now, if I drag and drop them onto my ArgsPrinter_c++.exe located directly on the C:\ drive, the result will be similar to this:

 argc = 27 argv[0] = C:\ArgsPrinter_c++.exe argv[1] = C:\Users\MyUserName\Desktop\c.txt argv[2] = C:\Users\MyUserName\Desktop\d.txt argv[3] = C:\Users\MyUserName\Desktop\e.txt argv[4] = C:\Users\MyUserName\Desktop\f.txt argv[5] = C:\Users\MyUserName\Desktop\g.txt argv[6] = C:\Users\MyUserName\Desktop\h.txt argv[7] = C:\Users\MyUserName\Desktop\i.txt argv[8] = C:\Users\MyUserName\Desktop\j.txt argv[9] = C:\Users\MyUserName\Desktop\k.txt argv[10] = C:\Users\MyUserName\Desktop\l.txt argv[11] = C:\Users\MyUserName\Desktop\m.txt argv[12] = C:\Users\MyUserName\Desktop\n.txt argv[13] = C:\Users\MyUserName\Desktop\o.txt argv[14] = C:\Users\MyUserName\Desktop\p.txt argv[15] = C:\Users\MyUserName\Desktop\q.txt argv[16] = C:\Users\MyUserName\Desktop\r.txt argv[17] = C:\Users\MyUserName\Desktop\s.txt argv[18] = C:\Users\MyUserName\Desktop\t.txt argv[19] = C:\Users\MyUserName\Desktop\u.txt argv[20] = C:\Users\MyUserName\Desktop\v.txt argv[21] = C:\Users\MyUserName\Desktop\w.txt argv[22] = C:\Users\MyUserName\Desktop\x.txt argv[23] = C:\Users\MyUserName\Desktop\y.txt argv[24] = C:\Users\MyUserName\Desktop\z.txt argv[25] = C:\Users\MyUserName\Desktop\a.txt argv[26] = C:\Users\MyUserName\Desktop\b.txt 

My ArgsPrinter_c++.exe source code:

 #include <iostream> using namespace std; int main(int argc, char* argv[]) { cout << "argc = " << argc << endl; for(int i = 0; i < argc; i++) cout << "argv[" << i << "] = " << argv[i] << endl; std::cin.ignore(); return 0; } 

Your last problem

I created a simple program that only creates the sceleton of your class so that it can be used, and the program itself ran JUST FINE => if your program exits too early, the problem will be in its class ...

Tested source code:

 #include <iostream> #include <vector> using namespace std; class Converter{ public: Converter(const char* f){ cout << f << endl; } void getATCommandsFromCSV(){ cout << "called getATCommandsFromCSV" << endl; } }; int main(int argc, char* argv[]) { vector<string> files; for (int g = 1; g < argc; g++) { string s = argv[g]; string filename = ""; int pos = s.find_last_of("\\", s.size()); if (pos != -1) { filename = s.substr(pos + 1); cout << "argv[1] " << argv[1] << endl; cout << "\n filename: " << filename << "\n pos: " << pos << endl; files.push_back(filename); } files.push_back(s); } for (unsigned int k = 0; k < files.size(); k++) { cout << "files.at( " << k << " ): " << files.at(k).c_str() << endl; Converter a(files.at(k).c_str()); a.getATCommandsFromCSV(); } cout << "\n" << "Programm finished...\n\n" << endl; cin.ignore(); return 0; }