Extract path from OpenFileDialog path / filename

Question

I am writing a small utility that starts with selecting a file, and then I need to select a folder. I would like to indicate by default the folder in which the selected file was selected.

OpenFileDialog.FileName returns the full path and file name - I want to get only part of the path (sans filename), so I can use this as the initial selected folder

private System.Windows.Forms.OpenFileDialog ofd; private System.Windows.Forms.FolderBrowserDialog fbd; ... if (ofd.ShowDialog() == DialogResult.OK) { string sourceFile = ofd.FileName; string sourceFolder = ???; } ... fbd.SelectedPath = sourceFolder; // set initial fbd.ShowDialog() folder if (fbd.ShowDialog() == DialogResult.OK) { ... } 

Are there any .NET methods for this, or do I need to use regex, split, trim, etc.

Answer 1

Use the Path class from System.IO . It contains useful calls for managing file paths, including GetDirectoryName , which does what you want by returning a portion of the file path directory.

The use is simple.

 string directoryPath = Path.GetDirectoryName(filePath); 

Answer 2

how about this:

 string fullPath = ofd.FileName; string fileName = ofd.SafeFileName; string path = fullPath.Replace(fileName, ""); 

Answer 3

 if (openFileDialog1.ShowDialog(this) == DialogResult.OK) { strfilename = openFileDialog1.InitialDirectory + openFileDialog1.FileName; } 

Answer 4

You can use FolderBrowserDialog instead of FileDialog and get the path from the OK result.

 FolderBrowserDialog browser = new FolderBrowserDialog(); string tempPath =""; if (browser.ShowDialog() == DialogResult.OK) { tempPath = browser.SelectedPath; // prints path } 

Answer 5

Here is an easy way to do it!

 string fullPath =openFileDialog1.FileName; string directory; directory = fullPath.Substring(0, fullPath.LastIndexOf('\\'));