Find a specific word in a text file and count it

Question

can someone help me with the code? How to search in a text file for any word and count how much it has been repeated?

For example test.txt:

hi hola hey hi bye hoola hi 

And if I want to know how many times the word "Hello" is repeated in test.txt, the program should say "3 times repeated"

I hope you understand what I want, thanks for the answers.

Answer 1

 public int countWord(String word, File file) { int count = 0; Scanner scanner = new Scanner(file); while (scanner.hasNextLine()) { String nextToken = scanner.next(); if (nextToken.equalsIgnoreCase(word)) count++; } return count; } 

Answer 2

 HashMap h=new HashMap(); FileInputStream fin=new FileInputStream("d:\\file.txt"); BufferedReader br=new BufferedReader(new InputStreamReader(fin)); String n; while((n=br.readLine())!=null) { if(h.containsKey(n)) { int i=(Integer)h.get(n); h.put(n,(i+1)); } else h.put(n, 1); } 

now iterate over this map to get a counter for each word, using each word as a key to the values ​​of the map

Answer 3

Use the MultiSet collection from google guava library .

 Multiset<String> wordsMultiset = HashMultiset.create(); Scanner scanner = new Scanner(fileName); while (scanner.hasNextLine()) { wordsMultiset.add(scanner.nextLine()); } for(Multiset.Entry<String> entry : wordsMultiset ){ System.out.println("Word : "+entry.getElement()+" count -> "+entry.getCount()); } 

Answer 4

Apache Commons - StringUtils.countMatches ()

Answer 5

 package File1; import java.io.BufferedReader; import java.io.FileReader; public class CountLineWordsDuplicateWords { public static void main(String[] args) { FileReader fr = null; BufferedReader br =null; String [] stringArray; int counLine = 0; int arrayLength ; String s=""; String stringLine=""; try{ fr = new FileReader("F:/Line.txt"); br = new BufferedReader(fr); while((s = br.readLine()) != null){ stringLine = stringLine + s; stringLine = stringLine + " ";/*Add space*/ counLine ++; } System.out.println(stringLine); stringArray = stringLine.split(" "); arrayLength = stringArray.length; System.out.println("The number of Words is "+arrayLength); /*Duplicate String count code */ for (int i = 0; i < arrayLength; i++) { int c = 1 ; for (int j = i+1; j < arrayLength; j++) { if(stringArray[i].equalsIgnoreCase(stringArray[j])){ c++; for (int j2 = j; j2 < arrayLength; j2++) { stringArray[j2] = stringArray[j2+1]; arrayLength = arrayLength - 1; } }//End of If block }//End of Inner for block System.out.println("The "+stringArray[i]+" present "+c+" times ."); }//End of Outer for block System.out.println("The number of Line is "+counLine); System.out.println(); fr.close(); br.close(); }catch (Exception e) { e.printStackTrace(); } }//End of main() method }//End of class CountLineWordsDuplicateWords 

Answer 6

 package somePackage; public static void main(String[] args) { String path = ""; //ADD YOUR PATH HERE String fileName = "test2.txt"; String testWord = "Macbeth"; //CHANGE THIS IF YOU WANT int tLen = testWord.length(); int wordCntr = 0; String file = path + fileName; boolean check; try{ FileInputStream fstream = new FileInputStream(file); BufferedReader br = new BufferedReader(new InputStreamReader(fstream)); String strLine; //Read File Line By Line while((strLine = br.readLine()) != null){ //check to see whether testWord occurs at least once in the line of text check = strLine.toLowerCase().contains(testWord.toLowerCase()); if(check){ //get the line, and parse its words into a String array String[] lineWords = strLine.split("\\s+"); for(String w : lineWords){ //first see if the word is as least as long as the testWord if(w.length() >= tLen){ /* 1) grab the specific word, minus whitespace 2) check to see whether the first part of it having same length as testWord is equivalent to testWord, ignoring case */ String word = w.substring(0,tLen).trim(); if(word.equalsIgnoreCase(testWord)){ wordCntr++; } } } } } System.out.println("total is: " + wordCntr); //Close the input stream br.close(); } catch(Exception e){ e.printStackTrace(); } } 

Answer 7

 public class Wordcount { public static void main(String[] args) { int count=0; String str="hi this is is is line"; String []s1=str.split(" "); for(int i=0;i<=s1.length-1;i++) { if(s1[i].equals("is")) { count++; } } System.out.println(count); } } 

Answer 8

You can read a text file line by line. I assume that each line can contain more than one word. For each line, you call:

 String[] words = line.split(" "); for(int i=0; i<words.length; i++){ if(words[i].equalsIgnoreCase(searhedWord)) count++; } 

Answer 9

try using java.util.Scanner.

 public int countWords(String w, String fileName) { int count = 0; Scanner scanner = new Scanner(inputFile); scanner.useDelimiter("[^a-zA-Z]"); // non alphabets act as delimeters String word = scanner.next(); if (word.equalsIgnoreCase(w)) count++; return count; } 

Answer 10

Try this with Pattern and Matcher .

 import java.io.BufferedReader; import java.io.File; import java.io.FileNotFoundException; import java.io.FileReader; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Dem { public static void main(String[] args){ try { File f = new File("d://My.txt"); FileReader fr = new FileReader(f); BufferedReader br = new BufferedReader(fr); String s = new String(); while((s=br.readLine())!=null){ s = s + s; } int count = 0; Pattern pat = Pattern.compile("it*"); Matcher mat = pat.matcher(s); while(mat.find()){ if(mat.find()){ mat.start(); count++; } } System.out.println(count); } catch (Exception e) { e.printStackTrace(); } } } 

Answer 11

 import java.io.*; import java.util.*; class filedemo { public static void main(String ar[])throws Exception BufferedReader br=new BufferedReader(new FileReader("c:/file.txt")); System.out.println("enter the string which you search"); Scanner ob=new Scanner(System.in); String str=ob.next(); String str1="",str2=""; int count=0; while((str1=br.readLine())!=null) { str2 +=str1; } int index = str2.indexOf(str); while (index != -1) { count++; str2 = str2.substring(index + 1); index = str2.indexOf(str); } System.out.println("Number of the occures="+count); } } 

Answer 12

 package com.test; import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.util.Scanner; public class Test { public static void main(String[] args) throws Exception{ BufferedReader bf= new BufferedReader(new FileReader("src/test.txt")); Scanner sc = new Scanner(System.in); String W=sc.next(); //String regex ="[\\w"+W+"]"; int count=0; //Pattern p = Pattern.compile(); String line=bf.readLine(); String s[]; do { s=line.split(" "); for(String a:s) { if(a.contains(W)) count++; } line=bf.readLine(); }while(line!=null); System.out.println(count); } } 

Answer 13

 public int occurrencesOfHi() { String newText = Text.replace("Hi",""); return (Text.length() - newText.length())/2; }