Just one row from sqlalchemy

Question

import re from sqlalchemy import * db = create_engine('sqlite:///code.db') db.echo = True metadata = MetaData(db) halo4 = Table('emblem_codes', metadata, autoload=True) ######################### ## Get One Unused Code ## ######################### s = select([halo4.c.code, halo4.c.status=='None']) result = s.execute() for row in result: print row 

My code returns all the results of 80999. I only want to. What is the best way to do this?

This is an example .db code:

 (u'JRQRY-MYHW3-D67GR-7YWFF-CRJ31', None) (u'9D7DR-4WFDY-VG49F-3DYCG-7DYT5', None) (u'QR9WT-P3CTM-PW4WW-34JJ4-RFKV7', None) (u'7FMXQ-H97TC-FFYC6-XHXFV-Y7KR2', None) (u'VKHXW-29WC4-4PF4Y-2QMJ4-4W2H4', None) 

Answer 1

If you want to get only one row from the ResultProxy object (which is the result of your s.execute() statement, you need to use fetchone() :

 s = select([halo4.c.code, halo4.c.status=='None']) result = s.execute() one_row = result.fetchone() another_row = result.fetchone()