You need to close the fds in the parent, or the child will not receive EOF because the channel is still open for writing in the parent. This will cause the second wait() to hang. Works for me:
#include <unistd.h> #include <stdlib.h> int main(int argc, char** argv) { int des_p[2]; if(pipe(des_p) == -1) { perror("Pipe failed"); exit(1); } if(fork() == 0) //first fork { close(STDOUT_FILENO); //closing stdout dup(des_p[1]); //replacing stdout with pipe write close(des_p[0]); //closing pipe read close(des_p[1]); const char* prog1[] = { "ls", "-l", 0}; execvp(prog1[0], prog1); perror("execvp of ls failed"); exit(1); } if(fork() == 0) //creating 2nd child { close(STDIN_FILENO); //closing stdin dup(des_p[0]); //replacing stdin with pipe read close(des_p[1]); //closing pipe write close(des_p[0]); const char* prog2[] = { "wc", "-l", 0}; execvp(prog2[0], prog2); perror("execvp of wc failed"); exit(1); } close(des_p[0]); close(des_p[1]); wait(0); wait(0); return 0; }
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