The same approach as in the original answer to the question is applicable here, with a slightly modified schedule:

Let's start by removing # 5. What remains is the paw graph (nodes (1,3,4,7)). Remove the leaves in any order. You discover an independent set of four - node: (1,3,5,7)
Start by removing # 6. There is a 4-cycle. Removing any node forces one of these sets:
both are three-element maximal (as in, cannot be extended) independent sets and, therefore, are not maximal (as in the case, as much as possible).
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