Not to steal the fame of Eugene, but here is a rather simple way to show, perhaps more strictly, that the general case of problems with the NP-hard poster.
Consider the minimal vertex hull of the problem of finding the minimal set X from vertices V to a simple graph ( V , E ), where each edge in E is adjacent to at least one vertex in X.
An edge can be represented by an unordered two-element set { v a , v b } where v a and v b are different elements in V. Note that an edge e represented as { v a , v b } next to v c if and only if v c is an element of { v a , v b }.
Therefore, the problem of the minimum coverage of vertices is the same as the search for a subset of the minimum size X of V , where each set of edges { v a , v b } defined by an edge in E contains an element that is in X>.
If you have an algorithm for effectively solving the original stated problem, then it has an algorithm for effectively solving the above problem, and therefore you can effectively solve the problem of minimum vertex coverage.
source share