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Bottled middleware to catch a certain type of exception?

Given this simple bottle code:

def bar(i): if i%2 == 0: return i raise MyError @route('/foo') def foo(): try: return bar() except MyError as e: response.status_code = e.pop('status_code') return e

How to write literary middleware so that the same exception handling is performed implicitly, so that such code can work identically above:

 @route('/foo') def foo(): return bar()
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3 answers

You can do it elegantly with the abort plugin:

 from bottle import abort def error_translation(func): def wrapper(*args,**kwargs): try: func(*args,**kwargs) except ValueError as e: abort(400, e.message) return wrapper app.install(error_translation)
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The bottle respects the wsgi specification. You can use the classic wsgi middleware

 from bottle import route, default_app, run, request # push an application in the AppStack default_app.push() @route('/foo') def foo(): raise KeyError() # error view @route('/error') def error(): return 'Sorry an error occured %(myapp.error)r' % request.environ # get the bottle application. can be a Bottle() instance too app = default_app.pop() app.catchall = False def error_catcher(environ, start_response): # maybe better to fake the start_response callable but this work try: return app.wsgi(environ, start_response) except Exception as e: # redirect to the error view if an exception is raised environ['PATH_INFO'] = '/error' environ['myapp.error'] = e return app.wsgi(environ, start_response) # serve the middleware instead of the applicatio run(app=error_catcher)
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Instead, you can use this:

 from bottle import error, run, route @error(500) def error_handler_500(error): return json.dumps({"status": "error", "message": str(error.exception)}) @route("/") def index(): a = {} a['aaa'] run()
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