There are four article in the template, so some 4n offset should do the trick. This seems to work ( Fiddle ):
article {color:blue} article:nth-child(4n-1), article:nth-child(4n-2) {color:green}
If you don't like minus, plus also works the same way ( Fiddle ):
article {color:blue} article:nth-child(4n+2), article:nth-child(4n+3) {color:green}
Just to explain all the logic, this is a matter of switching the 4n template:
4n-3 4n-2 4n-1
# COLOR 4n 4n + 1 4n + 2 4n + 3
- ------ ----- ------ ------ ------
1 blue - 0 - -
2 green - - 0 -
3 green - - - 0
4 blue 1 - - -
5 blue - 1 - -
6 green - - 1 -
7 green - - - 1
8 blue 2 - - -
9 blue - 2 - -
10 green - - 2 -
11 green - - - 2
12 blue 3 - - -
13 blue - 3 - -
-1 and +3 are congruent to mod 4, like -2 and +2 , so they relate to the same elements (although the value of n technically different for each).
You can even change it and the color 4n and 4n+1 blue ( Fiddle ):
article {color:green} article:nth-child(4n), article:nth-child(4n+1) {color:blue}
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