Geek Answers Handbook

Break a string into a specific index

If I have a string and I want to split it into. which is not in brackets, how would I do it.

'(1.2).(2.1)' to get ['(1.2)', '(2.1)']

'(1.2).2' to get ['(1.2)', '2']

'1.(1.2)' to get ['1', '(1.2)']

+6
source share
4 answers

This program assumes that the entry will always be valid, although it is fairly easy to include conditions for proper processing.

 def custom_split(data): element, opened, result = "", 0, [] for char in data: # Immediately following if..elif can be shortened like this # opened += (char == ")") - (char == "(") # Wrote like that for readability if char == ")": opened -= 1 elif char == "(": opened += 1 if char == "." and opened == 0 and element != "": result.append(element) element = "" else: element += char if element != "": result.append(element) return result print custom_split('(1.2).(2.1)') print custom_split('(1.2).2') print custom_split('2.2') print custom_split('(2.2)') print custom_split('2')

Output

 ['(1.2)', '(2.1)'] ['(1.2)', '2'] ['2', '2'] ['(2.2)'] ['2']
+3
source

This does not answer the general problem, but works for your examples:

 >>> import re >>> re.split(r'(?<=\))\.', '(1.2).(2.1)') ['(1.2)', '(2.1)'] >>> re.split(r'(?<=\))\.', '(1.2).2') ['(1.2)', '2']

This splits the string into any period after the closing parenthesis.

+3
source

Using re seems like a solution:

 >>> import re >>> r = re.compile(r'(?:[^.(]|\([^)]*\))+') >>> r.findall('(1.2).(2.1)') ['(1.2)', '(2.1)'] >>> r.findall('(1.2).2') ['(1.2)', '2'] >>> r.findall('1.(1.2)') ['1', '(1.2)']
+1
source 
 def split(s, level=0, result=''): if s == '': if result: return [result] else: return [] if s.startswith('.') and level == 0: return [result] + split(s[1:], 0, '') level += s.startswith('(') level -= s.startswith(')') return split(s[1:], level, result + s[0])

Using:

 >>> split('(1.2).(2.1)') ['(1.2)', '(2.1)'] >>> split('(1.2).2') ['(1.2)', '2'] >>> split('1.(1.2)') ['1', '(1.2)']
0
source

More articles:


All Articles